Hm, it sounds like a mod_rewrite issue, have a look at A Note on mod_rewrite.

I hope this helps!

I am an absolute newbie to cake php and the MVC design pattern itsef. I have basic understanding of working with php on my WAMP 2.0 local server. I am also pretty familiar with object oriented programming in C++. I was following the “blog tutorial” on the on the book.cakephp.org i followed everything exactly as there was in the tutorial. After completing the view of index of PostsController, they said it will display the blog posts already entered in the database. It was written that pointing the browser to “www.example.com/posts/index” will display all the entries in the database. As I am working on my local server I entered the URL as “localhost/test_cake/posts/index” and returned the notorious “404 object not found” test_cake is the name of the folder in my localhost www where i have extracted the cakephp 2.0 I have made all the names of everything exactly as it was given in the tutorial….. Somebody please help me with this… Thanks in advance….

If you really have to use the link method in the controller, have a look at How to use a helper in a controller.

Hope this helps.

After running it shows following errors on text box
Undefined variable: html [APP/controllers/members_controller.php, line 165]

Fatal error: Call to a member function link() on a non-object in /var/www/cakephp/app/controllers/members_controller.php on line 165

echo '<li onClick="fill(\''.addslashes($results['members']['name']).'\');">'. 
     $html->link($results['members']['name'], array(‘controller’ => ‘members’, ‘action’ => ‘view’)).
     '</li>';

Hope this helps.

And when click on the link it should redirect to the view of the
search result.( ie.to array(‘controller’ => ‘members’, ‘action’ =>
‘view’))

code :

echo '<li onClick="fill(\''.addslashes($results['members']
['name']).'\');">'.$results['members']['name'].'</li>';

I’m faild to add the link on it.
Plz help me.

And when click on the link it should redirect to the view of the
search result.( ie.to array(‘controller’ => ‘members’, ‘action’ =>
‘view’))

code :

echo ”.$results['members']['name'].”;

I’m faild to add the link on it.
Plz help me.

'contain' => array('Product')

to your $paginate array.

Hope that helps!

[URL=http://img412.imageshack.us/i/53074479.jpg/][IMG]http://img412.imageshack.us/img412/6611/53074479.th.jpg[/IMG][/URL]

the [B]ingredients[/B] of a product are saved in a table called [B]product_retetas[/B] and the records of that table have the following fields:
id | [B]product_id[/B] | [B]ingredient_id[/B] | …|…

[B]products[/B] have [B]hasAndBelongsToMany[/B] relationship with [B]ingredients[/B]
[B]products[/B] have [B]hasOne[/B] relationship with [B]product_retetas[/B]
[B]ingredients[/B] have [B]hasAndBelongsToMany[/B] relationship with [B]products[/B]
[B]product_retetas[/B] have [B]belogsTo[/B] relationship with both [B]ingredients[/B] and [B]products[/B]

——————————————————–

class ProductsController extends AppController {

var $name = ‘Products’;
var $helpers = array(‘Html’, ‘Form’);
/* var $paginate = array(
‘fields’=>array($this->query(‘distinct Product.id’)),
‘recursive’=>0,
‘limit’=>10 );*/

function index() {

$this->Product->recursive = 0;
$this->set(‘products’, $this->paginate());
}

If I set recursive la -2 then I will receive error in the index at every button (from the picture) becouse every button link is related to a model who belongs to product
(link(‘alergeni’,
array(‘controller’=> ‘product_retetas’, ‘action’=>’alergeni’,$product['Product']['id']),
array(‘target’=>’_blank’,'class’=>’btn’), null, false
);?>)

http://www.smartsms.tk